\(x\cdot\left(x+2\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=0\\x+2=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=-2\end{matrix}\right.\)
Vậy: \(x\in\left\{0;-2\right\}\)/
x . (x + 2) = 0
x + 2 = 0 : x
x + 2 = 0
x = 0 - 2
x = (-2)
x . (x + 2) = 0
x + 2 = 0 : x
x + 2 = 0
x = -2