\(\Rightarrow x^2-9-x^2+6x-9=-9\\ \Rightarrow6x=9\Rightarrow x=\dfrac{3}{2}\)
\(\left(x-3\right)\left(x+3\right)-\left(x-6\right)^2=-9\)
\(\Leftrightarrow x^2-9-x^2+12x-36=-9\)
\(\Leftrightarrow12x=36\Leftrightarrow x=3\)
\(\Rightarrow x^2-9-x^2+6x-9=-9\\ \Rightarrow6x=9\Rightarrow x=\dfrac{3}{2}\)
\(\left(x-3\right)\left(x+3\right)-\left(x-6\right)^2=-9\)
\(\Leftrightarrow x^2-9-x^2+12x-36=-9\)
\(\Leftrightarrow12x=36\Leftrightarrow x=3\)
Rút gọn
(x^4-3x^2+9).(x^2+3)-(3+x^2)
(x-3)^3-(x-3).(x^2+3x+9+6.(x+1)^2
Tìm x
(x-2)^3-(x-3).(x^2+3x+9)+6.(x+1)^2=49
(x+2).(x^2-2x+4-x.(x^2+2)=15
Bài 1: Tìm x:
1) (x-3)3 -( x-3)(x2+ 3x+9) +6( x+1)2+ 3x2 = -33
2) (X-3)( X2+ 3X+9) - X(X-2)( 2+X) = 1
3) (X+2)(X2 - 2X+4) – X(X-3)(X+3) = 26
tìm x
a,(x+1)^3-(x-1)^3-6(x-1)^2=-10
b,x(x+5)(x-5)-(x+2)(x^2-2x+4)=42
c,(x-2)^3-(x-3)(x^2+3x+9)+6(x+1)^2=49
Tìm x biết ( x – 6 ) ( x + 6 ) – ( x + 3 ) 2 = 9
A. x = -9
B. x = 9
C. x = 1
D. x = -6
Tìm x :
a) x (3x + 1) + (x -1)2 - (2x + 1)(2x -1) = 0
b) (x + 1)3 + (2 - x)3 - 9(x - 3)(x+3) = 0
c) (x - 1)3 - (x + 3)(x2 - 3x + 9) + 3x2 = 25
d) (x + 2)3 - ( x +1)(x2 - x + 1) - 6(x - 1)2 = 23
e) (x + 3)(x2 - 3x + 9) - x(x - 2)(x+2) + 11 = 0
f) x(x - 3) - x + 3 = 0
tìm x, biết :
d)(x - 3)(x^2 + 3x + 9) + x(x + 2)(2 - x) = 1
e) (x + 1)^3 - (x - 1)^3 - 6(x - 1)^2 = -19
(x-3)^3-(x-3)(x^2+3x+9)+6(x+1)=15. Tìm x
(x-3)^3-(x-3)(x^2+3x+9)+6(x+1)=15. Tìm x
Tìm đkxđ của: 1, 3x/ 4x-8 2, 2x/ x²-9 3, 6/x³+1 4, 6x²/x²-2x+1 5, x-2/x²+3 6, 2x/x²+3+2