Question

tìm x: (x-2)/(x-1)=(x+4)/(x+7)

Answer 1

\(\Rightarrow\left(x-2\right)\left(x+7\right)=\left(x-1\right)\left(x+4\right)\left(x\ne1;x\ne-7\right)\\ \Rightarrow x^2+5x-14=x^2+3x-4\\ \Rightarrow2x=10\Rightarrow x=5\left(tm\right)\)

Answer 2

\(\dfrac{x-2}{x-1}=\dfrac{x+4}{x+7}\\ \Rightarrow\left(x-2\right)\left(x+7\right)=\left(x-1\right)\left(x+4\right)\\ \Rightarrow x^2+5x-14=x^2+3x-4\\ \Rightarrow2x-10=0\\ \Rightarrow2x=10\\ \Rightarrow x=5\)