Question

Tìm x và y biết: \(\left|x-\dfrac{1}{2012}\right|+\left|x+y\right|=0\)

Answer 1

Do \(\left|x-\dfrac{1}{2012}\right|\) \(\ge0\); \(\left|x+y\right|\ge0\)

<=> \(\left\{{}\begin{matrix}\left|x-\dfrac{1}{2012}\right|=0\\\left|x+y\right|=0\end{matrix}\right.\) <=> \(\left\{{}\begin{matrix}x-\dfrac{1}{2012}=0\\x+y=0\end{matrix}\right.\)

<=> \(\left\{{}\begin{matrix}x=\dfrac{1}{2012}\\y=-x\end{matrix}\right.\) <=> \(\left\{{}\begin{matrix}x=\dfrac{1}{2012}\\y=\dfrac{-1}{2012}\end{matrix}\right.\)

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