\(\left(2x-15\right)^3=\left(2x-15\right)^5\\ \Rightarrow\left(2x-15\right)^2=1\\ \Rightarrow\left[{}\begin{matrix}2x-15=-1\\2x-15=1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=7\\x=8\end{matrix}\right.\)
giúp mik ik mik tic cho và nhớ cho thêm cả hướng dẫn
(2x−15)\(^3\)=(2x−15)\(^5\)
suy ra :(2x−15)\(^2\)=1
suy ra :2x−15= -1 Hoặc 2x - 15 = 1
2x = -1+15 HoĂc 2x = 1+15
2x = 14 hoĂc 2x = 16
x= 14: 2 hoĂc x= 16:2
x= 7 hoĂc x= 8
KL : x=7; x=8
Ta có: \(\left(2x-15\right)^5=\left(2x-15\right)^3\)
\(\Leftrightarrow\left(2x-15\right)^3\cdot\left(2x-16\right)\left(2x-14\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{15}{2}\\x=8\\x=7\end{matrix}\right.\)
