(x-5).(x-7)=0
=> x-5=0 hoặc x-7=0
=> x=0+5 hoặc x=0+7
=> x=5 hoặc x=7
(x-5).(x-7)=0
=> x-5=0 hoặc x-7=0
=> x=0+5 hoặc x=0+7
=> x=5 hoặc x=7
Tìm x thuộc z:
\(a,\left(x^2+5\right)\left(x^2-25\right)=0\)
\(b,\left(x-2\right)\left(x+1\right)=0\)
\(c,\left(x^2+7\right)\left(x^2-49\right)< 0\)
\(d,\left(x^2-7\right)\left(x^2-49\right)< 0\)
\(e,\left(x-1\right)\left(x-2\right)\left(x^2+4\right)>0\)
GIÚP MIK VS, MIK CẦN GẤP
Tìm x \(\in\)Z , biết:
a)(\(\left(x-4\right).\left(x+7\right)=0\)
b)\(x.\left(x+3\right)=0\)
c)\(\left(x-2\right).\left(5-x\right)=0\)
d)\(\left(x-1\right).\left(x^2+1\right)=0\)
Tìm các số nguyên x thỏa mãn :
a, \(\left(x-2\right)\left(x-7\right)< 0\)
b, \(\left(x^2-3\right)\left(x^2-10\right)< 0\)
c, \(\left(x^2-1\right)\left(x^2-4\right)\left(x^2-7\right)\left(x^2-10\right)< 0\)
d, \(\left(x^3+5\right)\left(x^3+10\right)\left(x^3+15\right)\left(x^3+30\right)< 0\)
Tìm x:
\(\left(\frac{1}{7}x-\frac{2}{7}\right)\left(-\frac{1}{5}x+\frac{3}{5}\right)\left(\frac{1}{3}x+\frac{4}{3}\right)=0\)
Tìm x biết
\(\left|2x-4\right|+\left|3y+12\right|+\left(2z-10\right)^{10}\le0\)
\(\left|x-3\right|+\left|2y-6\right|+\left(4x-3y\right)^2\le0\)
\(\left(x-7\right)\times\left(x+3\right)>0\)
\(\left(x-7\right)\times\left(x+3\right)\times\left(x-5\right)<0\)
tìm x\(\in\)Z
a, \((x^2+3)\left(x+7\right)=0\)
b,\(\left(x^2-1\right)\left(x^2-4\right)=0 \)
c,\(\left(5-x^2\right)\left(x^2-1\right)\ge0\)
tìm x thuộc Z
a) \(4\left(x-5\right)-7\left(5-x\right)+10\left(5-x\right)=-3\)
b) \(4\left|x-7\right|-3.\left(-5\right)=-2\left|x-7\right|-10\)
1.Tìm x,y thuộc z:
a,\(\left|2-x\right|+2=x\)
b,\(x+7=\left|x-9\right|\)
2.Tìm x,y thuộc z:
a,\(\left|x+10\right|+\left|5-y\right|=0\)
b,\(\left|x-40\right|+\left|x-y+10\right|=0\)
c,\(\left|x+y-30\right|+\left|x-y-4\right|=0\)
d,\(\left|x+y-15\right|+\left|xy-56\right|=0\)
GIÚP MIK VS Ạ, MIK ĐANG CẦN GẤP
Tìm x biết:
\(a,\left(x-\dfrac{3}{4}\right)+50\%=\dfrac{1}{6}\)
\(b,\dfrac{1}{2}x-\dfrac{5}{6}x=\dfrac{7}{2}\)
\(c,\left(4-x\right)\left(3x+5\right)=0\)
\(d,\dfrac{x}{16}=\dfrac{50}{32}\)
\(e,\left(2x-3\right)+\dfrac{3}{2}=-\dfrac{1}{4}\)
Tìm x:
a) \(\dfrac{1}{3}.x+\dfrac{2}{5}\left(x-1\right)=0\)
b)\(-5.\left(x+\dfrac{1}{5}\right)-\dfrac{1}{2}.\left(x-\dfrac{2}{3}\right)=x\)
c)\(\left(x+\dfrac{1}{2}\right).\left(\dfrac{2}{3}-2x\right)=0\)
d)\(9.\left(3x+1\right)^2=16\)