\(< =>\left(4x-1+x+7\right)\left(4x-1-x-7\right)=0< =>\left(5x+6\right)\left(3x-8\right)=0< =>\left\{{}\begin{matrix}5x+6=0\\3x-8=0\end{matrix}\right.< =>\left[{}\begin{matrix}x=-\dfrac{6}{5}\\x=\dfrac{8}{3}\end{matrix}\right.\)
(4x-1+x+7)(4x-1-x-7)= 0
(5x+6)(3x-8)= 0
=> 5x+6=0 hoặc 3x-8=0
=> x=1,2 hoặc x=8/3
vậy x= 1,2 hoặc x=8/3