`c, x^3 - 3x^2 + 3x - 2 = 0`
`<=> (x^3 - 3x^2 + 3x - 1) = 1`.
`<=> (x-1)^3 = 1`
`<=> x -1 = 1`
`<=> x=2`
Vậy `x= 2`
Tìm x:
C, X^2-9=2×(x+3)^2
b, x^3-3x^2+3x-1=0
d, x^2-8x+3x-24=0
Giúp mk với. Mk cảm ơn
Tìm x :
c, x^3 - 3x^2 + 3x - 2 = 0
tìm x biết
a/x^3+3x^2+3x+2=0
b/x^4-2x^3+2x-1=0
c/x^4-3x^3-6x^2+8x=0
Tìm x
a) 15x2-3x=0
b) (3x-2) (x+3)+ (x2-9)=0
c) (x-1)3- (x+1) (2-3x)=-3
Tìm x:
a,x(3x-5)=0
b,3x^2-27=0
c,(x-5)^2=x-5
d,2(x+7)-x^2-7x=0
e,7x(x-3)+2(3x)=0
Tìm x
a) (x + 3)2 + (x + 2)(5 – x) = 1
b/ (2x – 1)2 – ( x – 5)( 4x + 3) = 3
c/ 3x (x – 2) + 4x – 8 = 0
d/ 2x (3x + 5) – 18x – 30 = 0
Bài 2: Tìm x, biết: a) (x + 2)^2 – 2(x + 2)(x – 5) = 0. b) 2x^2 + 3x – 5 = 0. c) x + 2 ^2 x 2 + 2x^3 = 0. d) (3x-1)^2-4(x+5)^2=0
Tìm x:
a, 3x (4x -3) - 2x (5-6x) = 0
b, 5 (2x-3) + 4x (x-2) + 2x (3-2x) = 0
c, 3x (2-x) + 2x (x-1) = 5x (x+3)
d, 3x (x+1) - 5x (3-x) + 6(x2 + 2x + 3) = 0
Tìm x
a.(x+2).(x+3)-(x-2).(x+5) = 0
b. (2x+3).(x-4)+(x-5)(x+2) = (3x-5)(x-4)
c. (3x+2)(2x+9)-(x+2)(6x+1) = x+1-(x-6)
d. 3( 2x-1).(3x-1)-(2x-3).(9x-1)=0
