x = 2 đó mk đảm bảo 100% luôn
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Jup Gin ik mak TvT
1,\(\left(x+1\right)^3+\left(x-2\right)^3=\left(2x-1\right)^3\)
2,\(\left(x+1\right)^4+\left(x+3\right)^4=82\)
3,\(\left(x+1\right)\left(x+2\right)\left(x+3\right)\left(x+4\right)-24=0\)
4,\(\left(x^2-3x+2\right)\left(x^2+15x+56\right)+8=0\)
Giải các phương trình sau:
a/ \(\left(2x+1\right)\left(x+1\right)^2\left(2x+3\right)=18\)
b/ \(\left(x+1\right)^4+\left(x-3\right)^4=82\)
c/ \(\left(4-x\right)^5+\left(x-2\right)^5=32\)
d/ \(\left(x-7\right)^4+\left(x-8\right)^4=\left(15-2x\right)^4\)
tìm x, biết:
a) \(\left(3\text{x}+2\right)\left(x-1\right)-3\left(x+1\right)\left(x-2\right)=4\)
b) \(\left(3\text{x}-5\right)\left(7-5\text{x}\right)-\left(5\text{x}+2\right)\left(2-3\text{x}\right)=4\)
2 tháng 8 2016 lúc 13:23
tìm x biết
\(\frac{1}{\left(x-1\right)x}+\frac{1}{\left(x-2\right)\left(x-1\right)}+\frac{1}{\left(x-3\right)\left(x-2\right)}+\frac{1}{\left(x-4\right)\left(x-3\right)}=\frac{x}{x^2-4x}\)
giải pt
\(a,\left(x^2-5x\right)^2+10\left(x^2-5x\right)+24=0\)
\(b,\left(x-4\right)\left(x-5\right)\left(x-6\right)\left(x-7\right)=1680\)
\(c,\left(x+1\right)^4+\left(x-1\right)^4=82\)
d,\(\left(4-x\right)^5+\left(x+2\right)^5=32\)
Giải phương trình:
\(\left(x-\frac{1}{2}\right)^4+\left(x+\frac{3}{2}\right)^4=82\)
Tìm x, biết:
a) \(x\left(x-1\right)-x^2+2\text{x}=5\)
b) \(8\left(x-2\right)-2\left(3\text{x}-4\right)=2\)
c) \(\left(3\text{x}+2\right)\left(x-1\right)-3\left(x+1\right)\left(x-2\right)=4\)
d) \(\left(3\text{x}-5\right)\left(7-5\text{x}\right)-\left(5\text{x}+2\right)\left(2-3\text{x}\right)=4\)
Tìm x, biết:
\(\left(x-1\right)\left(x-2\right)\left(x-3\right)\left(x-4\right)=24\)
tìm x biết \(8\left(x+\frac{1}{x}\right)^2+4\left(x^2+\frac{1}{x^2}\right)^2-4\left(x^2+\frac{1}{x^2}\right)\left(x+\frac{1}{x}\right)^2=\left(x+4\right)^2...\)
ai làm nhanh và đúng thì đc 3 tick nha