Question

TÌM x BIẾT:

a)6(x+1)-3=2(x+2)+11

b)\(\frac{2x-1}{8}\)=\(\frac{x+7}{24}\)

c) (𝑥 + 2) ⋮ (2𝑥 − 1)

Answer 1

a) 6(x+1)-3=2(x+2)+11

6x + 6 - 3= 2x+ 4+11

6x-2x +6-3= 4+11

4x +6-3= 15

4x+6= 15+3

4x+6= 18

4x= 18-6

4x= 12

x= 12:4

x=3 

Vậy...

Answer 2

c) ( x+2 ) \(⋮\)( 2x-1)

=> 2x-1 \(⋮\)2x-1

=> ( x+2 ) - ( 2x-1)\(⋮\)2x-1

=> 2( x+2) - ( 2x-1) \(⋮\)2x-1

=> (2x+4)-(2x-1) \(⋮\)2x-1

=> 2x+4 - 2x+1 \(⋮\)2x-1

=> 5    \(⋮\)2x-1

=> 2x-1\(\in\)Ư(5) = { 1;5; -1;-5}

Xong b tự thay nha

Answer 3

b) Ta có : \(\frac{2x-1}{8}=\frac{x+7}{24}\)

\(\Rightarrow\left(2x-1\right).24=8\left(x+7\right)\)

\(48x-24=8x+56\)

\(48x-8x-24=56\)

\(40x-24=56\)

\(40x=56+24\)

\(40x=80\)

\(x=80:40\)

\(x=2\)

Vậy x=2

Answer 4

a) \(6\left(x+1\right)-3=2\left(x+2\right)+11\)

\(\Leftrightarrow6x+6-3=2x+4+11\)

\(\Leftrightarrow6x+3=2x+15\)

\(\Leftrightarrow6x-2x=15-3\)

\(\Leftrightarrow4x=12\)

\(\Leftrightarrow x=3\)

Vậy x=3

Answer 5

b) \(\frac{2x-1}{8}=\frac{x+7}{24}\)

\(\Leftrightarrow24\left(2x-1\right)=8\left(x+7\right)\)

\(\Leftrightarrow48x-24=8x+56\)

\(\Leftrightarrow48x-8x=56+24\)

\(\Leftrightarrow40x=80\)

\(\Leftrightarrow x=2\)

Vậy x=2