x(x - 15) = -50
x² - 15x + 50 = 0
x² - 10x - 5x + 50 = 0
(x² - 10x) - (5x - 50) = 0
x(x - 10) - 5(x - 10) = 0
(x - 10)(x - 5) = 0
x - 10 = 0 hoặc x - 5 = 0
*) x - 10 = 0
x = 0 + 10
x = 10
*) x - 5 = 0
x = 0 + 5
x = 5
Vậy x = 10; x = 5
\(x^2-15x=-50\)
\(x^2-2.x.\dfrac{15}{2}+\dfrac{225}{4}=\dfrac{25}{4}\)
\(\left(x-\dfrac{15}{2}\right)^2=\left(\dfrac{5}{2}\right)^2\)
\(\Leftrightarrow\left[{}\begin{matrix}x=10\\x=5\end{matrix}\right.\)