\(x^2-3x+2=0\\ < =>\left(x^2-x\right)+\left(-2x+2\right)=0\\ < =>x\left(x-1\right)-2\left(x-1\right)=0\\ < =>\left(x-1\right)\left(x-2\right)=0\\ < =>\left[{}\begin{matrix}x-1=0\\x-2=0\end{matrix}\right.\\ < =>\left[{}\begin{matrix}x=1\\x=2\end{matrix}\right.\)
Vậy: ...