\(x^2-3x=0\)
\(\Rightarrow x\left(x-3\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=0\\x-3=0\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=0\\x=3\end{matrix}\right.\)
Vậy \(x\in\left\{0;3\right\}\)
x² - 3x = 0
x(x - 3) = 0
x = 0 hoặc x - 3 = 0
*) x - 3 = 0
x = 0 + 3
x = 3
Vậy x = 0; x = 3