Có:
\(\left(x-5\right)^{x+2000}-\left(x-5\right)^{x+2000}.\left(x-5\right)^{16}=0\)
\(\Rightarrow\left(x-5\right)^{x+2000}.\left(1-\left(x-5\right)^{16}\right)=0\)
\(\orbr{\begin{cases}\left(x-5\right)^{x+2000}=0\\1-\left(x-5\right)^{16}=0\end{cases}\Rightarrow\orbr{\begin{cases}x-5=0\\\left(x-5\right)^{16}=1\end{cases}\Rightarrow}\orbr{\begin{cases}x=5\\\orbr{\begin{cases}x-5=1\\x-5=-1\end{cases}\Rightarrow}\orbr{\begin{cases}x=6\\x=4\end{cases}}\end{cases}}}\)
Vậy x thuộc 4;5;6.
Học tốt^^