Lời giải:
$2\frac{2}{6}x+8\frac{2}{3}=3\frac{1}{3}$
$\frac{7}{3}x=3\frac{1}{3}-8\frac{2}{3}=\frac{-16}{3}$
$x=\frac{-16}{3}: \frac{7}{3}=\frac{-16}{7}$
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$3\frac{2}{7}x-\frac{1}{8}=2\frac{3}{4}$
$\frac{23}{7}x=2\frac{3}{4}+\frac{1}{8}$
$\frac{23}{7}x=\frac{23}{8}$
$x=\frac{23}{8}: \frac{23}{7}=\frac{7}{8}$
Tìm x biết:
a)\(\frac{2}{3}.\left(x-\frac{3}{8}\right)-x-\left(-\frac{7}{8}+\frac{2}{3}\right)=\left(\frac{-3}{4}\right)^3:1\frac{11}{16}\)
b)\(-\frac{7}{8}+\frac{7}{8}:\left(\frac{2}{3}-x\right)+\frac{5}{6}:\left(-1\frac{11}{35}\right)=\left(0,8\right)^2\)
1 tìm x biết ;
a, 0-|x + 1| = 5
b, 2 - | \(\frac{3}{4}\)- x | = \(\frac{7}{12}\)
c, 2 | \(\frac{1}{2}\)x - \(\frac{1}{3}\)| - \(\frac{3}{2}\)= \(\frac{1}{4}\)
d, | x - \(\frac{1}{3}\)| = \(\frac{5}{6}\)
e, \(\frac{3}{4}\)- 2 | 2x - \(\frac{2}{3}\)| = 2
f, \(\frac{2x-1}{2}\)= \(\frac{5+3x}{3}\)
1 tìm x biết ;
a, 0-|x + 1| = 5
b, 2 - | \(\frac{3}{4}\)- x | = \(\frac{7}{12}\)
c, 2 | \(\frac{1}{2}\)x - \(\frac{1}{3}\)| - \(\frac{3}{2}\)= \(\frac{1}{4}\)
d, | x - \(\frac{1}{3}\)| = \(\frac{5}{6}\)
e, \(\frac{3}{4}\)- 2 | 2x - \(\frac{2}{3}\)| = 2
f, \(\frac{2x-1}{2}\)= \(\frac{5+3x}{3}\)
1. Tìm x:
a) \(\frac{-2}{3}x+\frac{1}{5}=\frac{-3}{10}\)
b) \(\frac{4}{7}x-\frac{9}{8}=-0,25\)
c) \(\left(50\%x+2\frac{1}{4}\right).\frac{-2}{3}=\frac{17}{6}\)
d) \(3\frac{1}{3}x+16\frac{3}{4}=-13,25\)
e) \(\frac{3}{4}x+\frac{2}{5}x=-1,25\)
Mong các bạn sẽ giúp đỡ mình nhiều cảm ơn mọi người
1 TÍNH NHANH
\(\frac{7}{6}-\left(0,25+\frac{7}{6}-2\frac{1}{3}\right)\)
\(\frac{3}{7}.\frac{-5}{8}+\frac{3}{7}.\frac{-3}{8}+\frac{5}{7}-7\)
2 TÌM X BIẾT
A ) \(x.\frac{3}{5}=\frac{6}{25}+\frac{-3}{5}\)
B ) \(\frac{7}{9}+\frac{4}{15}:x=\frac{13}{9}\)
CÓ LỜI GIẢI NHA
CẢM ƠN ĐÃ GIÚP MÌNH
2.TÌM X,BIẾT :
A) \(X-\frac{1}{4}=\frac{-3}{8}.\frac{2}{5};\)
B)\(\frac{X}{126}=\frac{-7}{24}.\frac{-6}{11}\)
GIÚP MÌNH NHÉ !!!!!!!!!!!!! GẤP LẮM XIN CẢM ƠN TRƯỚC
TRONG SÁCH GIÁO KHOA TOÁN 6 TẬP 2 VNEN TRANG 40
bài 15 tìm x biết
a\(\frac{x}{4}-\frac{3}{7}+\frac{2}{5}=\frac{31}{140}\)
b\(\frac{5}{12}+\frac{5}{x}-\frac{1}{8}=\frac{1}{2}\)
c\(x+\frac{1}{9}-\frac{3}{5}=\frac{3}{6}\)
d\(\frac{3}{4}-x+\frac{6}{-11}=\frac{5}{6}\)
e\(x-\frac{1}{9}-\frac{3}{5}=\frac{3}{6}\)
2.Tìm x
a) \(\frac{a}{b}x-\frac{7}{8}=\frac{1}{4}\)
b)\(\frac{3}{2}x-\frac{1}{2}=\frac{1}{3}:\left(\frac{-5}{6}\right)\)
c)\(\frac{2}{3}\left(x+\frac{5}{4}\right)-\frac{1}{3}\left(\frac{2}{3}-x\right)=\frac{4}{3}\)
Bài 8: Tìm số nguyên x biết
a) \(\left(\frac{-12}{27}+\frac{2}{3}\right)+\frac{-2}{9}\le x\le\left(\frac{11}{7}+\frac{2}{5}\right)+\frac{7}{5}+\frac{3}{7}\) b\(\frac{-x}{2}+\frac{2x}{3}+\frac{x+1}{4}+\frac{2x+1}{6}=\frac{8}{3}\)
c)\(\frac{3}{2x+1}+\frac{10}{4x+2}-\frac{6}{6x+3}=\frac{12}{26}\)
