a, \(\dfrac{x}{3}=\dfrac{8}{12};12:3=4\)\(;8:4=2\)
⇒\(x=\dfrac{2}{3}\)
a: \(\dfrac{x}{3}=\dfrac{8}{12}\)
nên x/3=2/3
hay x=2
b: \(x+\dfrac{1}{15}=\dfrac{1}{3}\)
\(\Leftrightarrow x=\dfrac{1}{3}-\dfrac{1}{15}=\dfrac{5}{15}-\dfrac{1}{15}=\dfrac{4}{15}\)
c: \(x\cdot\dfrac{4}{7}-\dfrac{2}{7}=\dfrac{5}{7}\)
\(\Leftrightarrow x\cdot\dfrac{4}{7}=\dfrac{5}{7}+\dfrac{2}{7}=1\)
hay x=7/4
d: \(\Leftrightarrow x\cdot\dfrac{3}{4}-\dfrac{5}{4}=-\dfrac{1}{2}\)
\(\Leftrightarrow x\cdot\dfrac{3}{4}=-\dfrac{2}{4}+\dfrac{5}{4}=\dfrac{3}{4}\)
hay x=1