23 tháng 10 2021 lúc 21:58
\(\dfrac{6x+5}{5x-3}=\dfrac{38-6x}{21-5x}\left(đk:x\ne\dfrac{5}{3},x\ne\dfrac{21}{5}\right)\)
\(\Rightarrow\left(6x+5\right)\left(21-5x\right)=\left(5x-3\right)\left(38-6x\right)\)
\(\Rightarrow-30x^2+101x+105=-30x^2+208x-114\)
\(\Rightarrow107x=219\Rightarrow x=\dfrac{219}{107}\left(tm\right)\)
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\(\dfrac{6x+5}{5x-3}=\dfrac{6x-38}{5x-21}\)
\(\Leftrightarrow30x^2-126x+25x-105=30x^2-18x-190x+114\)
\(\Leftrightarrow-101x-105=-208x+114\)
\(\Leftrightarrow107x=219\)
hay \(x=\dfrac{219}{107}\)
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