\(\dfrac{3}{4}+\dfrac{1}{4}\left(x-2\right)=1\)
⇔ \(\dfrac{1}{4}\left(x-2\right)=1-\dfrac{3}{4}=\dfrac{1}{4}\)
⇔ \(x-2=\dfrac{1}{4}:\dfrac{1}{4}=1\)
⇔ \(x=3\)
\(\dfrac{3}{4}+\dfrac{1}{4}\left(x-2\right)=1\)
\(\dfrac{1}{4}\left(x-2\right)=1-\dfrac{3}{4}=\dfrac{1}{4}\)
\(\left(x-2\right)=\dfrac{1}{4}\div\dfrac{1}{4}=1\)
\(x\) \(=1+2=3\)