a, 315-x=327-264
<=> 315-x=63
<=> x=315-63
<=>x=252
b, 147-x=10 x 5
<=> 147-x=50
<=> x= 147-50
<=> x=97
\(\left(315-x\right)+264=327\)
\(\left(315-x\right)=63\)
\(x=315-63\)
\(x=252\)
\(\left(147-x\right):5=10\)
\(\left(147-x\right)=50\)
\(x=147-50\)
\(x=97\)
( 315 - \(x\)) + 264 = 327
315 - \(x\) = 327 - 264
315 - \(x\) = 63
\(x\) = 315 - 63
\(x\) = 252
(147 - \(x\)) : 5 = 10
147 - \(x\) =10 \(\times\) 5
147 - \(x\) = 50
\(x\) = 147 - 50
\(x\) = 97