\(2x^2+3\left(x-1\right)\left(x+1\right)=5x\left(x+1\right)\)
\(\Leftrightarrow2x^2+3\left(x^2+x-x-1\right)=5x^2+5x\)
\(\Leftrightarrow2x^2+3\left(x^2-1\right)=5x^2+5x\)
\(\Leftrightarrow2x^2+3x^2-3=5x^2+5x\)
\(\Leftrightarrow5x^2-3=5x^2+5x\)
\(\Leftrightarrow5x=-3\)
\(\Leftrightarrow x=\dfrac{-3}{5}\)
Vậy \(x=\dfrac{-3}{5}\)