a) \(2x\left(5-3x^2\right)-10\left(6+x\right)\)
\(=10x-6x^3-60-10x\)
\(=\) \(-6x^3-60\)
a) \(2x\left(5-3x^2\right)-10\left(6+x\right)\\ =2x.5-2x.3x^2-10.6-10.x\\ =10x-6x^3-60-10x\)
b) \(3\left(-x+2\right)-6\left(1-x+5x^{20}\right)\\ =-3.x+3.2-6.1+6.x-5.5x^{20}\\ =-3x+6-6+6x-25x^{20}=25x^{20}+3x\)
c) \(7x\left(2-5x^2+\dfrac{1}{2}x^3\right)-14x\left(1-2x^2\right)\\ =7x.2-7x.5x^2+7x.\dfrac{1}{2}x^3-14x.1+14x.2x^2\\ =14x-25x^3+\dfrac{7}{2}x^4-14x+28x^3=3x^2+\dfrac{7}{2}x^4\)
b) \(3\left(-x+2\right)-6\left(1-x+5x^{20}\right)\)
\(=-3x+6-6+6x-30x^{20}\)
\(=3x-30x^{20}\)
c) \(7x\left(2-5x^2+\dfrac{1}{2}x^3\right)-14x\left(1-2x^2\right)\)
\(=14x-35x^3+3,5x^4-14x+28x^3\)
\(=-7x^3+3,5x^4\)
a) Ta có: \(2x\left(5-3x^2\right)-10\left(6+x\right)\)
\(=10x-6x^3-60-10x\)
\(=-6x^3-60\)
b) Ta có: \(-3\left(-x+2\right)-6\left(1-x+5x^{20}\right)\)
\(=3x-6-6+6x-30x^{20}\)
\(=-30x^{20}+9x-12\)
c) Ta có: \(7x\left(2-5x^2+\dfrac{1}{2}x^3\right)-14\left(1-2x^2\right)\)
\(=14-35x^3+\dfrac{7}{2}x^4-14+28x^2\)
\(=\dfrac{7}{2}x^4-35x^3+28x^2\)