a) \(x-\dfrac{3}{4}=6.\dfrac{3}{8}=\dfrac{9}{4}\)
\(\Rightarrow x=\dfrac{9}{4}+\dfrac{3}{4}=3\)
c) \(x+\dfrac{1}{2}.\dfrac{1}{3}=\dfrac{3}{4}\)
\(\Rightarrow x+\dfrac{1}{6}=\dfrac{3}{4}\Rightarrow x=\dfrac{3}{4}-\dfrac{1}{6}=\dfrac{9}{12}-\dfrac{2}{12}=\dfrac{7}{12}\)
Bạn xem lại đề c
b) \(\dfrac{7}{8}:x=3\dfrac{1}{2}\)
\(\Rightarrow\dfrac{7}{8}:x=\dfrac{7}{2}\)
\(\Rightarrow x=\dfrac{7}{8}:\dfrac{7}{2}\)
\(\Rightarrow x=\dfrac{1}{4}\)