Question

Tìm x

              a,     \(\left[x+11\right]^2=0\) 

              b,      \(\left[8-4x\right]^5=0\)

              c,      \(\left[16+3x\right]^{10}=0\)

Answer 1

a) (x+11)²=0

=>x+11=0

=>x=0-11=-11

b) (8-4x)⁵=0

=>8-4x=0

=>4x=8-0=8

=>x=8:4=2

c) (16+3x)¹⁰=0

=>16+3x=0

=>3x=0-16=-16

=>x=\(\frac{-16}{3}\)

Answer 2

a)x=-11

b) x = 2

c) x = -16/3

Answer 3

a) (x+11)²=0

=>x+11=0

=>x=0-11=-11

b) (8-4x)⁵=0

=>8-4x=0

=>4x=8-0=8

=>x=8:4=2

c) (16+3x)¹⁰=0

=>16+3x=0

=>3x=0-16=-16

=>x=\(\frac{-16}{3}\)

Answer 4

a. ( x+11)² = ( x + 11 ) (x + 11 ) = 0

=> ( x+ 11) = 0 => x= -11

b. ( 8 - 4x )⁵ = ( 8- 4x )⁴ (8 - 4x) =0

=> 8 - 4x=0 => 4x = 8 => x=2

c. ( 16 + 3x )¹⁰ = ( 16 + 3x )⁹ ( 16 + 3x ) = 0

=> ( 16 + 3x )=0 => 3x= -16

=> x = \(\frac{-16}{3}\)