\(5x\left(3-x\right)-x+3=0\\ < =>5x\left(3-x\right)-\left(x-3\right)=0\\ < =>5x\left(3-x\right)+\left(3-x\right)=0\\ < =>\left(3-x\right)\left(5x+1\right)=0\\ < =>\left[{}\begin{matrix}3-x=0\\5x+1=0\end{matrix}\right.\\ < =>\left[{}\begin{matrix}x=3\\5x=-1\end{matrix}\right.\\ < =>\left[{}\begin{matrix}x=3\\x=-\dfrac{1}{5}\end{matrix}\right.\)
Vậy: ...
5x(3-x)-x+3=0
=>5x(3-x)+(3-x)=0
=>(3-x)(5x+1)=0
=>\(\left[{}\begin{matrix}3-x=0\\5x+1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-\dfrac{1}{5}\end{matrix}\right.\)