(4x−3)−(x+5)=3(10−x)
⇒4x−3−x−5=30−3x
⇒3x−8=30−3x
⇒6x=38
3
Vậy 3
Lời giải:
$(4x-3)-(x+5)=3(10-x)$
$4x-3-x-5=30-3x$
$3x-8=30-3x$
$3x+3x=30+8$
$6x=38$
$x=\frac{38}{6}=\frac{19}{3}$
Ta có: 4x-3-(x+5)=3(10-x)
\(\Leftrightarrow4x-3-x-5=30-3x\)
\(\Leftrightarrow3x-8=30-3x\)
\(\Leftrightarrow6x=38\)
hay \(x=\dfrac{19}{3}\)