Question

tìm x \(2x^2-3x\left(x+1\right)=0\)

Answer 1

\(2x^2-3x\left(x+1\right)=0\)

\(\Rightarrow2x^2-3x^2-3x=0\)

\(\Rightarrow-x^2-3x=0\)

\(\Rightarrow-x\left(x+3\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}-x=0\\x+3=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=-3\end{matrix}\right.\)

Answer 2

x2 -3x2+3x=0 

-x2 +3x=0 

x(x-3)=0 

x=0 / x= 3