\(\left(27x+6\right):3-11=9\)
\(\Leftrightarrow27x+6=9\cdot11+3=102\)
hay \(x=\dfrac{32}{9}\)
\(\left(27x+6\right):3-11=9\\ \left(27x+6\right):3=20\\ \left(27x+6\right)=20\times3\\ 27x+6=60\\ 27x=54\\ x=2\)
Tìm x:
(27X+6):3-11=9
(27X+6):3 = 9+11
(27X+6):3 =20
(27X+6) =20x3
(27X+6) =60
27X =60-6
27X =54
X =54:27
X = 2