Question

tìm x

-2/3.x+1/5=1/10

Answer 1

\(=>x=\left(\dfrac{1}{10}-\dfrac{1}{5}\right):\dfrac{-2}{3}=\dfrac{-1}{10}:\dfrac{-2}{3}=-\dfrac{1}{10}\times\dfrac{-3}{2}=\dfrac{3}{20}\)

Answer 2

\(\dfrac{-2}{3}x+\dfrac{1}{5}=\dfrac{1}{10}\\ \dfrac{-2}{3}x=\dfrac{1}{10}-\dfrac{1}{5}\\ \dfrac{-2}{3}x=\dfrac{1}{10}-\dfrac{2}{10}\\ \dfrac{-2}{3}x=\dfrac{-1}{10}\\ x=\dfrac{-1}{10}:\dfrac{-2}{3}\\ x=\dfrac{-1}{10}.\dfrac{-3}{2}=\dfrac{3}{20}\)

\(∘Tai\)