(22+3).(x-5)+14=52+124:22
(4+3).(x-5)+14=25+124:4
7.(x-5)+14=25+31
7.(x-5)+14=56
7.(x-5)=42
x-5=6
x=11
Ta có: \(\left(2^2+3\right)\left(x-5\right)+14=5^2+124:2^2\)
\(\Leftrightarrow7\left(x-5\right)=25+31-14=42\)
\(\Leftrightarrow\left(x-5\right)=6\)
hay \(x=11\)