Question

Tìm x: (2-x)(3x+1)-x^2-x+6=0

Answer 1

\(\Leftrightarrow\left(x-2\right)\left(-3x-1\right)-\left(x^2+x-6\right)=0\)

\(\Leftrightarrow\left(x-2\right)\left(-3x-1\right)-\left(x+3\right)\left(x-2\right)=0\)

\(\Leftrightarrow\left(x-2\right)\left(-4x-4\right)=0\)

=>x=2 hoặc x=-1

Answer 2

Answer 3

\((2-x)(3x+1)-(2-x)(x+3)=0\)

<=>-4(x-2)(x+1)=0

=>x=2 hoac x=-1