a) 78=2.3.13
39=3.13
ƯCLN(78,39)=3X13=39;ƯC(78,39)=39;BCNN(78,39)=78;BC(78,39)=78
B)125=5^3
35=5.7
UCLN(125,35)=5;ƯC(125;35)=5;BCNN(125,25)=875;BC(125;25)=875
a)
UCLN(78,39) = 39 (vì 78 chia hết cho 39)
=> ƯC(78,39) = Ư(39) = {1;3;13;39}
BCNN(78,39) = 78 (vì 78 chia hết cho 39)
=> BC(78,39) = B(78) = {0;78;156;...}
b)
125 = 53
35 = 5 x 7
=> UCLN(125,35) = 5
=> ƯC(125,35) = Ư(5) = {1;5}
=> BCNN(125,35) = 53 x 7 = 875
=> BC(125,35) = B(875 = {0;875;1750;...}
a)ƯCLN(78;39)=39
ƯC(78;39)=Ư(39)={1;3;13;39}
BCNN(78;39)=78
BC(78;39)=B(78)={0;78;156;234;...}
b)ƯCLN(125;35)=5
ƯC(125;35)=Ư(5)={1;5}
BCNN(125;35)=875
BC(125;35)=B(875)={0;875;1750;2625;...}