Question

tìm số tự nhiên x để (x+13)chia hết cho (x-3)

Answer 1

\(x+13⋮x-3\)

=>\(x-3+16⋮x-3\)

=>\(16⋮x-3\)

=>\(x-3\in\left\{1;-1;2;-2;4;-4;8;-8;16;-16\right\}\)

=>\(x\in\left\{4;2;5;1;7;-1;11;-5;19;-13\right\}\)

mà x>=0

nên \(x\in\left\{4;2;5;1;7;11;19\right\}\)

Answer 2

\(x+13=x-3+16⋮\left(x-3\right)\\ \Rightarrow\left(x-3\right)\inƯ\left(16\right)\\ Ư\left(16\right)=\left\{-1;1;-2;2;-4;4;-8;8;-16;16\right\}\Rightarrow x\in\left\{2;4;1;5;-1;7;-5;11;-13;19\right\}\)

\(x\ge0=>\left\{2;4;1;5;7;11;19\right\}\)

Answer 3

sos cứu tui tìm số tự nhiên x để (x+13) chia hết cho (x-3)