2x(x-3) - x + 3 = 0
=>2x(x-3)-(x-3)=0
=>(x-3)(2x-1)=0
=>x-3 =0 hoặc 2x-1=0
=>x=3 hoặc x=
vậy S={3;}
`!`
`2x(x-3)-x+3=0`
`=> 2x(x-3)-(x-3)=0`
`=>(x-3)(2x-1)=0`
\(\Rightarrow\left[{}\begin{matrix}x-3=0\\2x-1=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=3\\x=\dfrac{1}{2}\end{matrix}\right.\)