a)
(2x-1)2=9
<=> 2x-1=\(\sqrt{9}\)
<=> 2x-1=3
<=> 2x=4
<=> x=2
b)
2x(x-3)=0
\(\Leftrightarrow\orbr{\begin{cases}x=0\\x-3=0\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=0\\x=3\end{cases}}\)
Vậy x=0 hoặc x=3
Tìm số nguyên x,biết:
a,(2x-1)2 = 9
\(\Rightarrow\left(2x-1\right)^2=3^2\)
\(\Rightarrow2x-1=3\)
\(\Rightarrow2x=4\Rightarrow x=2\)
b,2x(x-3) = 0
\(\Rightarrow\orbr{\begin{cases}2x=0\\x-3=0\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}x=0\\x=3\end{cases}}\)
giúp mik với!!
b.x=3
a. x=2
a) (2x-1)^2=3^2
Suy ra 2x-1=3
2x =3+1
2x =4
x =4:2
x=2
Vậy x=2
b)x-3=0:2
x-3=0
x =0+3
x =3
Vậy x=3
\(\text{a) }\left(2x-1\right)^2=9\)
\(\Rightarrow2x-1=\pm3\)
\(\cdot\text{TH1}:2x-1=3\text{ }\Leftrightarrow\text{ }2x=4\text{ }\Leftrightarrow\text{ }x=2\)
\(\cdot\text{TH2:}2x-1=-3\text{ }\Leftrightarrow\text{ }2x=-2\text{ }\Leftrightarrow\text{ }x=-1\)
\(\text{Vậy }x=\left\{-1;2\right\}\)
\(\text{b) }2x\left(x-3\right)=0\)
\(\Rightarrow2x=0\text{ hoặc }x-3=0\)
\(\Rightarrow x=0\text{ hoặc }x=3\)
\(\text{Vậy }x=\left\{0;3\right\}\)
a)\(\left(2x-1\right)^2=9\)
\(\Rightarrow\left(2x-1\right)^2=3^2\)
\(\Rightarrow2x-1=3\)
\(\Rightarrow2x=3-1\)
\(\Rightarrow2x=2\)
\(\Rightarrow x=2:2\)
\(\Rightarrow x=1\)
vậy x=1
a, (2x - 1)2 = 9
\(\Rightarrow\orbr{\begin{cases}\left(2x-1\right)^2=3^2\\\left(2x-1\right)^2=\left(-3\right)^2\end{cases}\Rightarrow\orbr{\begin{cases}2x-1=3\\2x-1=-3\end{cases}}}\Rightarrow\orbr{\begin{cases}2x=3+1=4\\2x=-3+1=2\end{cases}}\Rightarrow\orbr{\begin{cases}x=4\div2=2\\x=2\div2=1\end{cases}}\)
\(\Rightarrow x\in\left\{2;1\right\}\)
b, 2x(x - 3) = 0
\(\Rightarrow\orbr{\begin{cases}2x=0\\x-3=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=0\div2=0\\x=0+3=3\end{cases}}\)
\(\Rightarrow x\in\left\{0;3\right\}\)
