Để \(\frac{2x}{x-2}\)có giá trị nguyên thì :
\(2x⋮x+2\)
\(2x+4-4⋮x+2\)
\(2.\left(x+2\right)-4⋮x+2\)
vì \(2.\left(x+2\right)⋮x+2\)
\(\Rightarrow-4⋮x+2\)
\(\Rightarrow x+2\inƯC\left(-4\right)=\left\{-1;-2;-4;1;2;4\right\}\)
\(\Rightarrow x=\left\{-3;-4;-6;-1;0;2\right\}\)
Vậy để số hữu tỉ \(\frac{2x}{x-2}\)có giá trị nguyên thì \(x=\left\{-3;-4;-6;-1;0;2\right\}\)