\(1.\frac{4x+1}{3x-2}=-\frac{5}{4}\)
\(\Rightarrow\left(4x+1\right)\times4=\left(-5\right)\times\left(3x-2\right)\)
\(16x+4=\left(-15x\right)+10\)
\(16x+15x=10-4\)
\(31x=6\)
\(x=\frac{6}{31}\)
Vậy \(x\in\left\{\frac{6}{31}\right\}\)
\(2.\frac{x+5}{-7}=\frac{2x+3}{4}\)
\(\Rightarrow\left(x+5\right)\times4=\left(2x+3\right)\times\left(-7\right)\)
\(4x+20=\left(-14x\right)+\left(-21\right)\)
\(4x+14x=\left(-21\right)-20\)
\(18x=-41\)
\(x=-\frac{41}{18}\)
Vậy \(x\in\left\{-\frac{41}{18}\right\}\)