ai giúp mik dc ko ai làm đc mik cho 1000 like
\(x^2+5x-6=0\)
\(\Leftrightarrow x^2+6x-x-6=0\)
\(\Leftrightarrow x\left(x+6\right)-\left(x+6\right)=0\)
\(\Leftrightarrow\left(x+6\right)\left(x-1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x+6=0\\x-1=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-6\\x=1\end{matrix}\right.\)
\(S=\left\{-6,1\right\}\)
`x^2+5x-6=0`
`<=> x^2-x+6x-6=0`
`<=>x(x-1)+6(x-1)=0`
`<=>(x+6)(x-1)=0`
`<=>` \(\left[{}\begin{matrix}x=-6\\x=1\end{matrix}\right.\)
Vậy `S={-6;1}`.
Cho A(x)=0
=>x^2+5x-6=0
=>x^2+6x-x-6=0
=>x(x+6)-(x+6)=0
=>(x+6)(x-1)=0
=>x+6=0 hoặc x-1=0
+)x+6=0 => x=-6
+)x-1 =0 =>x=1
Vậy x thuộc {-6;1}