Question

tìm hiệu x-y biết: \(\frac{x+3}{y+5}=\frac{x+5}{y+7}\)

Answer 1

\(\frac{x+3}{y+5}=\frac{x+5}{y+7}=\frac{x+5-x-3}{y+7-y-5}=\frac{2}{2}=1\)

=> x+3 = y+5

=> x -y = 5 -3 =2

Vậy x -y =2

Answer 2

\(\Rightarrow\left(x+3\right)\left(y+7\right)=\left(x+5\right)\left(y+5\right)\)

\(\Rightarrow xy+7x+3y+21=xy+5x+5y+25\)

\(\Rightarrow2x-2y=4\Rightarrow x-y=2\)

Answer 3

\(\frac{x+3}{y+5}=\frac{x+5}{y+7}\)

=>(x+3).(y+7)=(x+5).(y+5)

=>x.y+7x+3y+21=xy+5x+5y+25

=>2x-2y=4

=>2(x-y)=4

=>x-y=4:2

=>x-y=2