Question

Tìm GTNN Của biểu thức sau

Answer 1

GTLN hay GTNN?

Answer 2

\(-\left|2-3x\right|\le0\forall x\)

\(\Leftrightarrow-\left|3x-2\right|+\dfrac{1}{2}\le\dfrac{1}{2}\forall x\)

Dấu '=' xảy ra khi \(x=\dfrac{2}{3}\)

Answer 3

\(C=-\left|2-3x\right|+\dfrac{1}{2}\le-0+\dfrac{1}{2}=\dfrac{1}{2}\)

\(\Rightarrow maxC=\dfrac{1}{2}\Leftrightarrow2-3x=0\Leftrightarrow x=\dfrac{2}{3}\)