→\(A=-3\left(x^2+\dfrac{7}{3}x-2\right)\)
\(=-3\left[x^2+2.\dfrac{7}{6}.x+\left(\dfrac{7}{6}\right)^2-\dfrac{121}{36}\right]\)
\(=-3\left[\left(x+\dfrac{7}{6}\right)^2-\dfrac{121}{36}\right]\)
\(=\dfrac{121}{36}-3\left(x+\dfrac{7}{6}\right)^2\le\dfrac{121}{36}\)
dấu ''='' xảy ra khi A=121/36 ⇔\(x=-\dfrac{7}{6}\)