a) aba x aa = aaaa
aba = aaaa : aa
aba = 101
=> a = 1 ; b = 0
b) a x b x ba = aaa
b x ba = aaa : a
b x ba = 111
=> a=1
b x b1 = 111
b x b x 10 +1 = 111
b x b x 10 = 111 -1
b x b x 10 = 110
b x b = 110 : 10
b xb = 11
=> b = 3 , 316625
Ta có:
a, \(aba\times aa=aaaa\)
\(\Leftrightarrow aba=aaaa\div aa\)
\(\Leftrightarrow aba=101\)
\(\Rightarrow a=1\); \(b=0\)
Vậy \(a=1\)và \(b=0\)
Ta có:
a, \(aba\times aa=aaaa\)
\(\Leftrightarrow aba=aaaa\div aa\)
\(\Leftrightarrow aba=101\)
\(\Rightarrow a=1;b=0\)
Vậy \(a=1;b=0\)
b, \(a\times b\times ba=aaa\)
\(\Leftrightarrow b\times ba=aaa\div a\)
\(\Leftrightarrow b\times ba=111\)
\(\Leftrightarrow b\times ba=3\times37\)
\(\Rightarrow a=7;b=3\)
Vậy \(a=7;b=3\)
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