Ta có: \(\left|2x-1\right|=x-1\)
\(\Leftrightarrow\left[{}\begin{matrix}2x-1=x-1\left(x\ge\dfrac{1}{2}\right)\\2x-1=1-x\left(x< \dfrac{1}{2}\right)\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\left(loại\right)\\x=\dfrac{2}{3}\left(loại\right)\end{matrix}\right.\)