Đặt \(\dfrac{a}{3}=\dfrac{b}{4}=\dfrac{c}{5}=k\Rightarrow a=3k,b=4k,c=5k\)
Có: \(3k.5k=60\)
\(\Rightarrow15k^2=60\Rightarrow k^2=4\Rightarrow k=\pm2\)
TH1: \(k=2\)
\(\Rightarrow\left\{{}\begin{matrix}a=3k=6\\b=4k=8\\c=5k=10\end{matrix}\right.\)
TH2: \(k=-2\)
\(\Rightarrow\left\{{}\begin{matrix}a=3k=-6\\b=4k=-8\\c=5k=-10\end{matrix}\right.\)
Đặt a/3=b/4=c/5=k
=>a=3k; b=4k; c=5k
Ta có: ac=60
\(\Leftrightarrow15k^2=60\)
\(\Leftrightarrow k^2=4\)
TH1: k=2
=>a=6; b=8; c=10
TH2: k=-2
=>a=-6; b=-8; c=-10