\(\lim\limits_{x\rightarrow3}\left(\dfrac{1}{x}-\dfrac{1}{3}\right)\dfrac{1}{\left(x-3\right)^3}=\lim\limits_{x\rightarrow3}\dfrac{1}{3x\left(x-3\right)^2}=+\infty\)
Đúng 1
Bình luận (0)
\(\lim\limits_{x\rightarrow1}\dfrac{x^3-\sqrt{3x+2}}{x-1}=\dfrac{1^3-\sqrt{3.1+2}}{1-1}=-\infty\)
Đúng 1
Bình luận (0)