ab + A +B = 63
=> so ab ≤ 63, nen a+b ≤ 6+3 hay a+b ≤ 9
vi a+b ≤ 9 nen => A=B (1)
Theo de bai ta co A = a+b (2)
Thay (1) va (2) vao de bai, ta co:
ab +2(a+b) = 63 10a + b + 2a + 2b = 63
4a + b = 21b = (21 - 4a)
Vi a,b la chu so, nen 0≤a,b≤ 9, hay 0≤21-4a ≤9 => a=3;4;5
Neu a=3 => b=9 => loai (vi a+b =12>9)
Neu a=4 => b=5 (chon)
Neu a=5 => b=1 (chon)
Vay so can tim la 45 hoac 51
Tìm số có 2 chữ số ab biết :
a)ab+a+b=48
b) 57-ab=a+b
c) 63-(a+b) =ab
Tìm số tự nhiên ab biết a+b=9 và ba-ab=63
Biet AxB=0 mà A+4.b=41 . tìm ab
tìm a,b biet 900:(a+b)=ab
tra loi cach lam
ab=a.b . biet ab=a+b tinh a va b
tim ab biet
bbb=a*b*ab
Cho cac so nguyen duong a,b,c,x,y,z
1, Biet 1/a = 3/b + c = 5/c + a. Hay rut gon phan so A = a/2b - c
2. Biet a/b = 2b/cc = 4c/a. Hay rut gon phan so B = ab + bc + ca/a2 + b + c2
3. Biet x/a = y/b =z/c. Hay rut gon phan so C = x*y*z*(b+c)*(c+a)*(a+b)/a*b*c(y+z)*(z+x)*(x+y)
4. Biet ab/a + 2b = 2/5; bc/b + 2c = 3/4; ca/c +2a = 3/5. Hay rut gon phan so D = abc/ab+bc+ca
5. Biet 3/a -4b = 5c. Hay rut gon phan so E = 3bc + ab - 4ac/6bc - 8ac -ab
Giup minh nhe! Ai lam duoc va dung cho tick.
Thanks cac ban
Cho cac so nguyen duong a,b,c,x,y,z
1, Biet 1/a = 3/b + c = 5/c + a. Hay rut gon phan so A = a/2b - c
2. Biet a/b = 2b/cc = 4c/a. Hay rut gon phan so B = ab + bc + ca/a2 + b + c2
3. Biet x/a = y/b =z/c. Hay rut gon phan so C = x*y*z*(b+c)*(c+a)*(a+b)/a*b*c(y+z)*(z+x)*(x+y)
4. Biet ab/a + 2b = 2/5; bc/b + 2c = 3/4; ca/c +2a = 3/5. Hay rut gon phan so D = abc/ab+bc+ca
5. Biet 3/a -4b = 5c. Hay rut gon phan so E = 3bc + ab - 4ac/6bc - 8ac -ab
Giup minh nhe! Ai lam duoc va dung cho tick.
Thanks cac ban
