\(\dfrac{6}{2-\sqrt{10}}-\dfrac{2\sqrt{5}-5\sqrt{2}}{\sqrt{2}-\sqrt{5}}+\sqrt{41+4\sqrt{10}}\\ =\dfrac{6\left(2+\sqrt{10}\right)}{4-10}-\dfrac{\sqrt{10}\left(\sqrt{2}-\sqrt{5}\right)}{\sqrt{2}-\sqrt{5}}+\sqrt{\left(2\sqrt{10+1}\right)^2}\\ =-2-\sqrt{10}-\sqrt{10}+\left|2\sqrt{10}+1\right|\\ =-2-2\sqrt{10}+2\sqrt{10}+1\\=-2+1\\ =-1\)