a. \(\left(2x+1\right)^2-4x\left(x-1\right)=4x^2+4x+1-4x^2+4x=8x+1\)
b. \(\left(x-2\right)\left(x+2\right)-\left(x-1\right)^2=x^2-4-x^2+2x-1=2x-5\)
a)\((2x+1)^2-4x(x-1)=4x^2+4x+1-4x^2+4x\)
=\(8x+ 1\)
b)\((X-2)(x+2)-(x-1)^2=X^2-4-(x^2-2x+1)\)
=\(X^2-4-x^2+2x-1=2x-5\)
a: \(\left(2x+1\right)^2-4x\left(x-1\right)\)
\(=4x^2+4x+1-4x^2+4x\)
=8x+1
b: \(\left(x-2\right)\left(x+2\right)-\left(x-1\right)^2\)
\(=x^2-4-x^2+2x-1\)
=2x-5