Question

thực hiện phép tính

2011-5x5²-\([\)7³:7+2012⁰\(]\)

120:520:\([\)500-5³+35x7\(]\)

Answer 1

\(2011-5.5^2-\left(7^3:7+2012^0\right)\\ =2011-5^3-\left(7^2+1\right)\\ =2011-125-50=1836\)

\(120:520:\left(500-5^3+35.7\right)\\ =120:520:\left(500-125+245\right)\\ =120:520:620=\dfrac{3}{8060}\)

Answer 2

\(2011-5\times5^2-\left[7^3:7+2012^0\right]\\ =2011-5^3-\left(7^2+1\right)\\ =2011-125-50\\ =1836\\ 120:520:\left[500-5^3+35\times7\right]\\ =120:520:\left[500-125+35\times7\right]\\ =120:520:620\\ =\dfrac{3}{8060}\)

Answer 3

a: \(2011-5\cdot5^2-\left[7^3:7+2012^0\right]\)

\(=2011-125-\left(7^2+1\right)\)

\(=1836\)

b: \(120:520:\left[500-5^3+35\cdot7\right]\)

\(=120:520:620\)

\(=\dfrac{3}{8060}\)