Question

Thực hiện phép tính (X+1)(x²-x+1); (x-3)(x²+3x+9) giúp mình với ạ

Answer 1

`th1:`

`(x+1)(x^2-x+1):(x-3)(x^2+3x+9)`

`=(x^3+1^3):(x^3-3^3)`

`=(x^3+1):(x^3-27)`

`=(x^3+1)/(x^3-27)`

`=(x^3-27+28)/(x^3-27)`

`=1+28/(x^3-27)`

`**th2:`

`(x+1)(x^2-x+1)`

`=x^3+1^3=x^3+1`

`(x-3)(x^2+3x+9)`

`=x^3-3^3=x^3-27`

Answer 2

\(\left(x+1\right)\left(x^2-x+1\right)=x^3+1\)

\(\left(x-3\right)\left(x^2+3x+9\right)=x^3-27\)