\(50\%+\dfrac{7}{12}-\dfrac{1}{2}\)
\(=\dfrac{1}{2}+\dfrac{7}{12}-\dfrac{1}{2}\)
\(=\left(\dfrac{1}{2}-\dfrac{1}{2}\right)+\dfrac{7}{12}\)
\(=\dfrac{7}{12}\)
_______________
\(2022\cdot67+2022\cdot43-2022\cdot10\)
\(=2022\cdot\left(67+43-10\right)\)
\(=2022\cdot100\)
\(=202200\)
_____________________
\(10,3+6,9+8,7+13,1\)
\(=\left(13,1+6,9\right)+\left(10,3+8,7\right)\)
\(=20+19\)
\(=39\)
___________________
\(17,58\times43+57\times17,58\)
\(=17,58\times\left(43+57\right)\)
\(=17,58\times100\)
\(=1758\)
tớ ghi sai nên cập nhật lại câu hỏi, phần 3 các bạn trả lời sớm mà bị sai thì bỏ qua cho tớ nhé
\(50\%+\dfrac{7}{12}-\dfrac{1}{2}=\dfrac{1}{2}+\dfrac{7}{12}-\dfrac{1}{2}=\left(\dfrac{1}{2}-\dfrac{1}{2}\right)+\dfrac{7}{12}=\dfrac{7}{12}\)
\(2022\cdot67+2022\cdot43-2022\cdot10=2022\cdot\left(67+43-10\right)=2022\cdot100=202200\)
\(11,3+6,9+8,7+13,1=\left(11,3+8,7\right)+\left(6,9+13,1\right)=20+20=40\)
\(17,58\cdot43+57\cdot17,58=17,58\cdot\left(43+57\right)=17,58\cdot100=1758\)
